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char* solution£¨int n£© {
char * answer = £¨char*£©malloc£¨£¨n * 3£© + 1£©;
for £¨int i = 0; i < n ; i++£© {
if £¨i % 2 == 0£©
strcpy£¨answer+£¨i*3£©, "¼ö"£©;
else
strcpy£¨answer+£¨i*3£©, "¹Ú"£©;
}
return answer;
}
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